What is the moment of inertia of a pendulum with a mass of #7 kg# that is #4 m# from the pivot?

1 Answer
Jan 13, 2016

Answer:

#112kg.m^2#

Explanation:

Assuming this is a simple pendulum, ie the mass and dimensions of the pendulum bob is small compared to its overall dimensions, we may simple approximate its moment of inertia as follows :

#I=MR^2#

#=7xx4^2#

#=112kg.m^2#.

(If however the pendulum is compound, then one would need to use alternative formulae involving centre of mass and precise definitions of #I#).