# What is the moment of inertia of a pendulum with a mass of 7 kg that is 5 m from the pivot?

Apr 12, 2017

moment of inertia = $175 k g \cdot {m}^{2}$

#### Explanation:

As the mass of the connecting rod is not given it means that it is weightless we can ignore it.

$\textcolor{red}{I = m {r}^{2}}$

Where I is moment of inertia
m is mass
r is the distance from pivot

$I = 7 \cdot {5}^{2}$

$175 k g \cdot {m}^{2}$