# What is the moment of inertia of a pendulum with a mass of 7 kg that is 7 m from the pivot?

Feb 24, 2018

I got $343 \setminus {\text{kg"*"m}}^{2}$.

#### Explanation:

The moment of inertia of a simple pendulum is given by

$I = m {r}^{2}$, where $m$ is the mass of the pendulum in kilograms, and $r$ is the distance of the pendulum from the pivot in meters.

So here, we got $m = 7 \setminus \text{kg", r=7 \ "m}$.

$\therefore I = 7 \setminus {\text{kg"*49 \ "m}}^{2}$

$= 343 \setminus {\text{kg"*"m}}^{2}$