# What is the moment of inertia of a pendulum with a mass of 8 kg that is 10 m from the pivot?

Jan 26, 2016

$800 k g . {m}^{2}$

#### Explanation:

Assuming it is a simple pendulum, we may find the moment of inertia as

$I = M {R}^{2}$

$= 8 \times {10}^{2}$

$= 800 k g . {m}^{2}$