What is the moment of inertia of a pendulum with a mass of #9 kg# that is #10 m# from the pivot?

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Answer 1 · 2018-08-14T02:53:41

#900 \ "kg m"^2#

Moment of inertia of a simple pendulum is given by the equation:

#I=mr^2#

where:

#m# is the mass of the pendulum's bob in kilograms

#r# is the distance of the pendulum's bob from the pivot

So, we get:

#I=9 \ "kg"*(10 \ "m")^2#

#=9 \ "kg"*100 \ "m"^2#

#=900 \ "kg m"^2#