# What is the moment of inertia of a pendulum with a mass of 9 kg that is 10 m from the pivot?

Aug 14, 2018

$900 \setminus {\text{kg m}}^{2}$

#### Explanation:

Moment of inertia of a simple pendulum is given by the equation:

$I = m {r}^{2}$

where:

• $m$ is the mass of the pendulum's bob in kilograms

• $r$ is the distance of the pendulum's bob from the pivot

So, we get:

I=9 \ "kg"*(10 \ "m")^2

$= 9 \setminus {\text{kg"*100 \ "m}}^{2}$

$= 900 \setminus {\text{kg m}}^{2}$