# What is the moment of inertia of a pendulum with a mass of 9 kg that is 11 m from the pivot?

May 31, 2017

The moment of inertia is $= 1089 k g {m}^{2}$

#### Explanation:

We assume that it is a point mass.

The moment of inertia is

$I = m {r}^{2}$

The mass is $m = 9 k g$

The distance is $r = 11 m$

The moment of inertia is

$I = m {r}^{2} = 9 \cdot {11}^{2} = 1089 k g {m}^{2}$