# What is the moment of inertia of a pendulum with a mass of 9 kg that is 7 m from the pivot?

Jul 6, 2018

#### Answer:

The moment of inertia is $= 441 k g {m}^{2}$

#### Explanation:

The moment of inertia is

$I = m {r}^{2}$

The mass of the pendulum is $= 9 k g$

The distance from the pivot is $r = 7 m$

Therefore,

$I = 9 \cdot {7}^{2} = 441 k g {m}^{2}$