What is the moment of inertia of a rod with a mass of 3 kg and length of 12 m that is spinning around its center?

The moment of inertia is $= 36 k g {m}^{2}$
The moment of inertia of a rod is $I = \frac{1}{12} \cdot m {L}^{2}$
$= \frac{1}{12} \cdot 3 \cdot {12}^{2} = 36 k g {m}^{2}$