What is the moment of inertia of a rod with a mass of 6 kg and length of 25 m that is spinning around its center?

Jan 1, 2017

The answer is $= 12.5 k g {m}^{2}$

Explanation:

The moment of inertia of a rod (spinning around its center) is

$I = \frac{1}{12} \cdot m {L}^{2}$

$m = 6 k g$

$L = 25 m$

Therefore,

$I = \frac{1}{12} \cdot 6 \cdot 25 = 12.5 k g {m}^{2}$