# What is the moment of inertia of a rod with a mass of 6 kg and length of 5 m that is spinning around its center?

Mar 14, 2018

$I = 12.5 \setminus {\textrm{k g m}}^{2}$

#### Explanation:

Moment of inertia of rod with rotational axis about its center is given as:

$I = \frac{1}{12} m {l}^{2}$

We are given $m = 6$ kg and $l = 5$ m.

$I = \frac{1}{12} \left(6\right) {\left(5\right)}^{2} = 12.5 \setminus {\textrm{k g m}}^{2}$