# What is the NaCl ppm in seawater if the concentration is (salt to water as in seawater) 3,5% ?

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anor277 Share
Feb 10, 2018

So, in $100 \cdot g$ of solution there are $3.5 \cdot g$ of salt, and the balance water?

#### Explanation:

By definition...$\text{1 ppm} = \frac{1 \cdot m g}{1 \cdot L}$...most of the time we can ignore the density because the mass of the solute is miniscule...here we assume that the $96.5 \cdot g$ of solvent water expresses a volume of $96.5 \cdot m L$...

And so we take the quotient....

$\frac{3.5 \cdot g \times {10}^{3} \cdot m g \cdot {g}^{-} 1}{96.5 \cdot m L \times {10}^{-} 3 \cdot L \cdot m {L}^{-} 1} = 36 , 269 \cdot \text{ppm}$

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