What is the net ionic equation of the reaction of BeCl_2 with NaOH?

$B {e}^{2 +} + 2 H {O}^{-} \rightarrow B e {\left(O H\right)}_{2} \left(s\right) \downarrow$
Beryllium hydroxide is only slightly soluble in water. At high $p H$, it can form the beryllate complex ion, $B e {\left(O H\right)}_{4}^{2 -}$.