# What is the norm of < 7 , -2, -1 >?

Aug 2, 2016

$| | A | | = 3 \sqrt{6} \text{ unit}$

#### Explanation:

$A = < 7 , - 2 , - 1 >$

$| | A | | = \sqrt{{7}^{2} + {\left(- 2\right)}^{2} + {\left(- 1\right)}^{2}}$

$| A | | = \sqrt{49 + 4 + 1}$

$| | A | | = \sqrt{54}$

$| | A | | = \sqrt{9 \cdot 6}$

$| | A | | = 3 \sqrt{6} \text{ unit}$