What is the norm or #<-7 , 5, 1 >#?

1 Answer
Dec 7, 2016

Answer:

# | < -7, 5, 1 > | = 5sqrt(3) #

Explanation:

# \ \ \ \ \ | < -7, 5, 1 > | = | ( (-7), (5), (1) ) | #
# :. | < -7, 5, 1 > | = ( (-7), (5), (1) ) * ( (-7), (5), (1) ) #
# :. | < -7, 5, 1 > | = sqrt( (-7)^2 + (5)^2, +(1)^2 ) #
# :. | < -7, 5, 1 > | = sqrt( 49+25+1) #
# :. | < -7, 5, 1 > | = sqrt( 75) #
# :. | < -7, 5, 1 > | = sqrt( 25*3) #
# :. | < -7, 5, 1 > | = 5sqrt(3) #