Question

What is the [OH−] for a 0.026 M solution of Sr(OH)2?

Answer 1

`0.052 \ "M"`

Explanation:

We have the dissociation of `Sr(OH)_2`:

`Sr(OH)_2(s)->Sr^(2+)(aq)+2OH^(-)(aq)`

And so, one mole of strontium hydroxide contains two moles of hydroxide ions.

Therefore, the `[OH^-]` here will be `0.026 \ "M"*2=0.052 \ "M"`.