What is the oxidation number of N in NH4NO3 ?

1 Answer
anor277
Apr 23, 2018

#-III# and #+V#

Explanation:

As always, the sum of the oxidation numbers in an ion OR a molecule is equal to the charge of the ion or molecule. Here we gots a neutral salt composed of ammonium and nitrate ions. The oxidation number of oxygen is here #-II#, and that of hydrogen #+I#. Sum all the oxidation numbers together and you get ZERO, appropriate for a neutral salt.

And so we get a formal assignment of #stackrel(""^(-)III)NH_4^+stackrel(V^+)NO_3^-#

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