# What is the percent difference between the acceleration due to gravity at sea level and at the uppermost peak of Mount Everest?

The acceleration due to gravity at sea level is ${\text{9.78719 m/s}}^{2}$.
The acceleration due to gravity at the top of Mount Everest is ${\text{9.766322 m/s}}^{2}$. http://www.physicsclassroom.com/class/1DKin/Lesson-5/Acceleration-of-Gravity
Average = ($\text{9.78719 m/s"^2 + "9.766322 m/s"^2}$)$/$$\text{2}$ = ${\text{9.77676m/s}}^{2}$
Percent difference = ($\text{9.78719 m/s"^2 - "9.766322 m/s"^2}$)$\div$${\text{9.77676m/s}}^{2}$ x $\text{100}$ = $\text{0.21347%}$