Question

What is the percent of water by mass for the hydrate, `BaCl_2 * 2H_2O`?

Answer 1

Approx. 15%

Explanation:

`(2xx18.01*cancelg*cancel(mol^-1))/(244.26*cancelg*cancel(mol^-1))xx100% = ????`

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Here is another example of how to calculate %water in a hydrate.