What is the perimeter of a triangle with vertices located at #(1, 3), (2,6),# and #(0, 4),# rounded to the nearest hundredth?

1 Answer
Binayaka C.
Aug 6, 2016

Perimeter of the triangle is #7.40# unit

Explanation:

Side#AB=sqrt((1-2)^2+(3-6)^2)=sqrt10=3.16#
Side#BC=sqrt((2-0)^2+(6-4)^2)=sqrt8=2.83#
Side#CA=sqrt((0-1)^2+(4-3)^2)=sqrt2=1.41#
Perimeter of the triangle is #3.16+2.83+1.41 =7.40#unit[Ans]

Related questions
Impact of this question
6828 views around the world
You can reuse this answer
Creative Commons License