What is the period and amplitude for I(t) =120 sin (10pix - pi/4)?

1 Answer
Jun 5, 2015

A general time-dependent wave function can be represented in the following form:

y = A*sin(kx-omegat)

where,
A is amplitude
omega = (2pi)/T where T is time period
k = (2pi)/lamda where lamda is the wavelength

So, comparing with the given equation I(t) =120 sin (10pix - pi/4), we can find:

Amplitude (A) = 120

Now, your supplied equation has no t- dependent parameter in the sine function, whereas the L.H.S. clearly indicates it is a time-dependent function [I(t)]. So, this is impossible!

Probably, your equation was supposed to be I(t) =120 sin (10pix - pi/4t)

Under that condition,
omega = pi/4
=> pi/4 = (2pi)/T
=> T = 8 units