# What is the period of f(t)=sin( ( 11t) /6 )?

$\frac{12 \pi}{11}$
the amplitude = |a| , period = $\frac{2 \pi}{b} \text{ and c is phase shift }$
here b = $\frac{11}{6} \Rightarrow \text{ period } = \frac{2 \pi}{\frac{11}{6}} = \frac{12 \pi}{11}$