What is the period of #f(t)=sin( ( 7 t ) /3 ) #?
1 Answer
Jan 15, 2016
period =
#6/7pi #
Explanation:
The period of sint is
#2pi # The period of sin2t is
#pi =( 2pi)/2 # To find the period of sin(nt) divide
# (2pi)/n #
#rArr sin((7t)/3) period =( 2pi)/(7/3) =2pi xx 3/7 =6/7pi #
