# What is the period of f(t)=sin( ( 7 t ) /3 ) ?

Jan 15, 2016

period = $\frac{6}{7} \pi$

#### Explanation:

The period of sint is $2 \pi$

The period of sin2t is $\pi = \frac{2 \pi}{2}$

To find the period of sin(nt) divide $\frac{2 \pi}{n}$

$\Rightarrow \sin \left(\frac{7 t}{3}\right) p e r i o d = \frac{2 \pi}{\frac{7}{3}} = 2 \pi \times \frac{3}{7} = \frac{6}{7} \pi$