Question

What is the period of `f(theta) = tan ( ( 5theta)/12 )- cos ( ( 3 theta)/ 4 )`?

Answer 1

`24pi`

Explanation:

Period of `tan ((5t)/12) --> (12pi)/5`
Period of `cos ((3pi)/4) --> (8pi)/3`
Period of f(t) is the least common multiple of `(12pi)/5 and (8pi)/3`

(12pi)/5 x (10) -->`24pi`

(8pi)/3 x (9) ---> `24pi`

Answer: Period of f(t) ---> `24pi`