# What is the polar form of ( -1,3 )?

Dec 8, 2015

Polar form is $\left(r , \theta\right)$

#### Explanation:

$r = \sqrt{{\left(- 1\right)}^{2} + {\left(3\right)}^{2}} = \sqrt{10}$

The point is in quadrant II ...

reference angle $= {\tan}^{-} 1 \left(\frac{3}{1}\right) = {71.565}^{o}$

$\theta = 180 - 71.565 = {108.435}^{o}$

polar form $= \left(\sqrt{10} , {108.435}^{o}\right)$

hope that helped