# What is the polar form of ( 10,12 )?

Jan 31, 2016

$\left(15.62 , {50.19}^{\circ}\right)$

#### Explanation:

we know, polar form of a point is
$\left(r , \theta\right)$

$r = \sqrt{{x}^{2} + {y}^{2}}$

$= \sqrt{{10}^{2} + {12}^{2}}$

$= \sqrt{244}$

$= 15.62$

$\theta = {\tan}^{- 1} \left(\frac{12}{10}\right)$

$= {\tan}^{- 1} \left(1.2\right)$

$= {50.19}^{\circ}$