# What is the polarity of Cl_2O?

There is a permanent dipole moment in the $C {l}_{2} O$ molecule, analogous (but much less in magnitude) to that of the water molecule.
And thus we draw $\stackrel{\delta +}{C} l - \stackrel{\delta -}{O} - \stackrel{\delta +}{C} l$ in that oxygen is SLIGHTLY more electronegative than chlorine.
$\angle C l - O - C l = {110.9}^{\circ}$, and $C l - O = 1.70 \times {10}^{-} 10 \cdot m$.