Question

What is the polynomial `f(x)` of degree 3 that has the zeroes `1, 0, -9`?

Answer 1

`f(x)=` `x^3+8x^2-9x`

Explanation:

`f(x)=(x-1)(x+9)(x)`

`=>` `(x^2+9x-x-9)x`

`=>` `(x^2+8x-9)x`

`=>` `x^3+8x^2-9x`