# What is the probability that a card chosen at random from a standard deck of cards will be a number card?

$\frac{36}{52} = \frac{9}{13}$

#### Explanation:

I'm going to assume that by "number card" we're talking about 2 through 10 (the Ace being the "1" card).

In a standard deck, there are 9 ordinal cards that are numbered out of a total of 13 ordinal cards (the remaining ones are the Ace, Jack, Queen, King).

Each ordinal has 1 card in each of four suits (hearts, spades, clubs, diamonds), for a total of 52 cards in total ($13 \times 4 = 52$).

There are $9 \times 4 = 36$ cards we can pull that will be number cards from a standard deck, which makes the probability:

$\frac{36}{52} = \frac{9}{13}$