What is the product of #(6-5i) and (3+2i)# , expressed in #a+bi# form?

Question

531 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-01-30T07:49:11

The answer is #=28-3i#

We need

#i^2=-1#

Therefore,

#(6-5i)(3+2i)=18+12i-15i-10i^2#

#=18-10i^2+12i-15i#

#=18+10-3i#

#=28-3i#