What is the product of #(x^2-1)/(x+1)# and #(x+3)/(3x-3)# expressed in simplest form?

1 Answer
Jun 10, 2017

Product of #(x^2-1)/(x+1)# and #(x+3)/(3x-3)# is #(x+3)/3#

Explanation:

#(x^2-1)/(x+1)xx(x+3)/(3x-3)#

= #((x+1)(x-1))/(x+1)xx(x+3)/(3(x-1))#

= #(cancel((x+1))cancel((x-1)))/cancel((x+1))xx(x+3)/(3(cancel(x-1)))#

= #(x+3)/3#