What is the range of the function #f(x) = 2/(x-1)#?

1 Answer
May 14, 2017

Answer:

#y inRR,y!=0#

Explanation:

#"rearrange f(x) making x the subject"#

#rArry=2/(x-1)#

#rArry(x-1)=2#

#rArrxy-y=2#

#rArrxy=2+y#

#rArrx=(2+y)/y#

The denominator cannot be zero as this would make it #color(blue)"undefined"# Equating the denominator to zero and solving gives the value that y cannot be.

#rArry=0larrcolor(red)"excluded value"#

#rArr"range is " y inRR,y!=0#