What is the range of the function #f(x) = 2/(x-1)#?
1 Answer
May 14, 2017
Explanation:
#"rearrange f(x) making x the subject"#
#rArry=2/(x-1)#
#rArry(x-1)=2#
#rArrxy-y=2#
#rArrxy=2+y#
#rArrx=(2+y)/y# The denominator cannot be zero as this would make it
#color(blue)"undefined"# Equating the denominator to zero and solving gives the value that y cannot be.
#rArry=0larrcolor(red)"excluded value"#
#rArr"range is " y inRR,y!=0#
