# What is the range of the function  sqrt(2x-8)?

May 1, 2017

Range $\ge 0$

#### Explanation:

There are two rules about square roots:
(1)
The argument must be non-negative, or $2 x - 8 \ge 0$
This means the domain is restricted to $x \ge 4$
(2)
The function has a non-negative outxome. Since everything down to $0$ is possible (when $x = 4$) the range is $\ge 0$