What is the range of the function #sqrt(6x-7)#?

1 Answer
Nov 2, 2017

Answer:

Range#= [0,+oo)#

Explanation:

As the things inside square root cannot be negative, #6x-7# must be bigger than or equal to #0#.

#6x-7>=0#

#6x>=7#

#x>=7/6#

Domain#=[7/6, +oo)#

Since the things inside square root is bigger than or equal to #0#, the range of #sqrt(k)# is the value from #sqrt(0)# to #sqrt(+oo)#, whatever the value of #k#.

Range#= [0,+oo)#