# What is the range of the function sqrt(6x-7)?

Nov 2, 2017

Range$= \left[0 , + \infty\right)$

#### Explanation:

As the things inside square root cannot be negative, $6 x - 7$ must be bigger than or equal to $0$.

$6 x - 7 \ge 0$

$6 x \ge 7$

$x \ge \frac{7}{6}$

Domain$= \left[\frac{7}{6} , + \infty\right)$

Since the things inside square root is bigger than or equal to $0$, the range of $\sqrt{k}$ is the value from $\sqrt{0}$ to $\sqrt{+ \infty}$, whatever the value of $k$.

Range$= \left[0 , + \infty\right)$