What is the range of the function #y=8x-3#?

2 Answers
Nov 29, 2017

Answer:

Range of #y# is #(-oo,+oo)#

Explanation:

#y=8x-3#

First note that #y# is a straight line with slope of #8# and #y-#intercept of #-3#

The range of a function is the set of all valid outputs ("#y-# values") over its domain.

The domain of all straight lines (other than the vertical ones) is #(-oo,+oo)# since they are defined for all values of #x#

Hence, the domain of #y# is #(-oo,+oo)#

Also, since #y# has no upper or lower bounds, the range of #y# is also #(-oo,+oo)#

Nov 29, 2017

Answer:

#-oo<=y<=oo# (all real numbers (#R#))

Explanation:

Just remember that the range for a linear function is always all real numbers unless it is horizontal (doesn't have #x#).

One example of a linear function with a range of not all real numbers would be #f(x)=3#. The range for this function would be #y=3#.

I hope that helps!