# What is the range of the function y = -x^2 + 1?

The range is: $\left(- \infty , 1\right]$
The domain of $f \left(x\right)$ is $\setminus m a t h \boldsymbol{R}$
So for every $x$ that you put in the function $y \setminus \le q 1$, that means is the upper bound of the function.