What is the slope-intercept form of the line passing through  (-3, -5)  and  (0, 6) ?

The Slope intercept form of the line is $y = \frac{11}{3} \cdot x + 6$
The Slope of the line is $\frac{{y}_{2} - {y}_{1}}{{x}_{2} - {x}_{1}} \mathmr{and} \frac{6 + 5}{0 + 3} \mathmr{and} \frac{11}{3}$
The line passes through (0,6) So the equation of the line is$y - 6 = \frac{11}{3} \cdot \left(x - 0\right) \mathmr{and} y = \frac{11}{3} \cdot x + 6$ Here the y-intercept is 6. We can also find the x-intercept by putting y=0 in the equation . Then $0 = \frac{11}{3} \cdot x + 6 \mathmr{and} \frac{11}{3} \cdot x = - 6 \mathmr{and} x = - \frac{18}{11}$ So x- intercept is$- \frac{18}{11} \left[a n s w e r\right]$ graph{11/3*x+6 [-20, 20, -10.42, 10.42]}