# What is the slope-intercept form of the line passing through (6, 1)  and  (-4, 1) ?

Feb 27, 2016

y = 1

#### Explanation:

The slope-intercept form of the line is y = mx + c , where m represents the gradient (slope) and c , the y-intercept.

Require to calculate m using $\textcolor{b l u e}{\text{ gradient formula }}$

$m = \frac{{y}_{2} - {y}_{1}}{{x}_{2} - {x}_{1}}$

where $\left({x}_{1} , {y}_{1}\right) \text{ and " (x_2,y_2) " are the coords of 2 points }$

here let$\left({x}_{1} , {y}_{1}\right) = \left(6 , 1\right) \text{ and } \left({x}_{2} , {y}_{2}\right) = \left(- 4 , 1\right)$

hence $m = \frac{1 - 1}{- 4 - 6} = 0$

m = 0 , indicates this line is parallel to the x-axis , with equation y = a , where a , are the y-coords of points it passes through. Here that is 1.

hence equation is y = 1