# What is the slope of any line perpendicular to the line passing through (-9,8) and (0,0)?

Jan 14, 2016

First, find the slope of the original line.

#### Explanation:

m = $\frac{{y}_{2} - {y}_{1}}{{x}_{2} - {x}_{1}}$

m = $\frac{0 - 8}{0 - \left(- 9\right)}$

m = $- \frac{8}{9}$

The slope of a line perpendicular to that line would be the negative reciprocal. To find this, invert the numerator and the denominator and multiply by -1, which gives you m = $\frac{9}{8}$

So, the slope of any line perpendicular to the line passing through (-9, 8) and (0,0) is $\frac{9}{8}$.