Question

What is the slope of the line tangent to the graph of `y = arctan(3x)` at x = 1?

Answer 1

First determine the derivative of the function with respect to x, then evaluate at x = 1.

Explanation:

`dy/dx` = `3/(1 + (3x)^2)` = `3/(1+9x^2`

Evaluating at x = 1:

slope = `3/(1+9)=3/10`

hope that helped!