What is the slope of the line tangent to the graph of y = arctan(3x) at x = 1?

Sep 28, 2015

First determine the derivative of the function with respect to x, then evaluate at x = 1.

Explanation:

$\frac{\mathrm{dy}}{\mathrm{dx}}$ = $\frac{3}{1 + {\left(3 x\right)}^{2}}$ = 3/(1+9x^2

Evaluating at x = 1:

slope = $\frac{3}{1 + 9} = \frac{3}{10}$

hope that helped!