# What is the slope of the tangent line of r=(sin^2theta)/(2theta-thetacos2theta) at theta=(pi)/4?

##### 1 Answer
Jan 15, 2018

slope is the derivative value at a given value of $\theta$

#### Explanation:

dr/d$\theta$
by quotient rule:
it is
$\frac{2 \sin \theta \cos \theta \left(2 \theta - \theta \cos 2 \theta\right) - \left({\sin}^{2} \theta\right) \left(2 - \left(\cos 2 \theta + \theta \left(- \sin 2 \theta\right) \cdot 2\right)\right)}{2 \theta - \theta \cos 2 \theta} ^ 2$
now placing the value of $\theta = \frac{\pi}{4}$
you can find slope
hope u find it helpful :)