Question

What is the solution for the system of equations `3y + 2x = 4` and `2y-6x=-12`?

Answer 1

Multiplying the first by 3 yields `9y+6x=12`, adding to the second `11y=0` so `y=0` and `x=2`.

Answer 2

`x=2`
`y=0`

Explanation:

1. `3 y+2 x=4`
2. `2 y- 6 x=-12`

Multiply the first equation by 3:
`9 y+6 x=12`
Sum equation (1.)+(2.):
`9 y+6 x=12` |+
`2 y- 6 x=-12`
`9 y+ 2 y +6 x-6 x=12-12`
`11 y+0=0` `=>` `y=0`

Put `y=0` in one equation for example the first:
`3*0+2 x=4`
`x=4/2=2`