What is the solution to the question; The hydrogen ion concentration of a sample of orange juice is #2.0×10^-11mol# #dm^-3#. What is its #"pOH"#?

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1s2s2p Share
Mar 9, 2018

Answer:

#"pOH"=3.30#

Explanation:

#"pOH"=-log([OH^-])=-log(K_w/([H^+]))#

#K_w=1*10^-14#
#[H^+]=2.0*10^-11#

#"pOH"=-log((1*10^-14)/(2.0*10^-11))=3.30#

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