Question

What is the standard equation of a circle with center (0, 2) that passes through (5, -2)?

Answer 1

The distance between the center and the point is the radius of the circle has

`r=sqrt[(0-5)^2+(2-(-2))^2]=sqrt(25+16)=sqrt41`

Hence the equation of the circle is

`(x-0)^2+(y-2)^2=(sqrt41)^2`