# What is the standard form of a polynomial (x-3)^2(x-1) ?

Mar 13, 2018

${x}^{3} - 7 {x}^{2} + 15 x - 9$

#### Explanation:

First multiply out the squared bracket:
$\left({x}^{2} - 6 x + 9\right) \left(x - 1\right)$

Then multiply out the brackets and simplify:
${x}^{3} - {x}^{2} - 6 {x}^{2} + 6 x + 9 x - 9$ =
${x}^{3} - 7 {x}^{2} + 15 x - 9$