# What is the standard form of y=(2x-1)(3x+4) ?

Jan 13, 2016

$y = 6 {x}^{2} + 5 x - 4$

#### Explanation:

Distribute this using the FOIL method.

$y = \left(2 x - 1\right) \left(3 x + 4\right) = {\overbrace{2 x \cdot 3 x}}^{\text{First"+overbrace(2x*4)^"Outside"+overbrace(-1*3x)^"Inside"+overbrace(-1*4)^"Last}}$

$= 6 {x}^{2} + 8 x - 3 x - 4$

Combine like terms.

$= 6 {x}^{2} + 5 x - 4$

This is in standard form since the exponents are in descending order.