# What is the standard form of y=x(3x^2-9) ?

Jan 8, 2016

$y = 3 {x}^{3} - 9 x$

#### Explanation:

Simply distribute the $x$ by multiplying it.

$y = x \left(3 {x}^{2}\right) - x \left(9\right)$

$y = 3 {x}^{3} - 9 x$

This is in standard form since the exponents are in descending order.