What is the sum of the geometric series for which #a_1 = 3, r=2, n=12#?

1 Answer
Aug 20, 2016

#S_n = 12,285#

Explanation:

All the information we need has been given. Now it is a matter of knowing which formula to use and substituting the given numbers.

For a GP where #r > 1: " " S_n = (a_1(r^n - 1))/((r-1))#

#S_n = (3(2^12 - 1))/(2-1)#

#S_n = 3(4,095)#

#S_n = 12,285#