What is the surface area of a right rectangular prism whose dimensions are 3 feet by 6 feet by 8 feet?

1 Answer
Shwetank Mauria
Dec 22, 2016

Surface area of a right rectangular prism is #180# square feet.

Explanation:

If the dimension of a right rectangular prism are #l# - the length, #b# - breadth (or width) and #h# - the height. and if open this up by cutting along its edges as shown below,

http://www.ask-math.com/surface-area-of-rectangular-prism.html

It is apparent that surface area of a prism is

#lxxh+lxxb+lxxh+lxxb+bxxh+bxxh# or

#2xx(lxxh+lxxb+bxxh)#

Hence surface area of the given prism, whose dimensions are #3# feet by #6# feet by #8# feet, is

#2xx(3xx6+6xx8+8xx3)#

= #2xx(18+48+24)#

= #2xx90=180# square feet.

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