# What is the temperature of 350 mL of gas at .85 atm if it has a volume of 920 mL at STP?

May 7, 2016

$88.3 K$

#### Explanation:

Use the equation:

$\frac{{P}_{1} \cdot {V}_{1}}{{T}_{1}} = \frac{{P}_{2} \cdot {V}_{2}}{T} _ 2$

Where ${P}_{1}$ is the pressure at STP, ${T}_{1}$ is the temperature at STP and ${V}_{1}$ is $0.92 L$.

Substitute all the values in.

$\frac{\left(1 a t m\right) \left(0.92 L\right)}{273 K} = \frac{\left(0.85 a t m\right) \left(0.35 L\right)}{T} _ 2$

$\left({T}_{2}\right) \left(0.92 L\right) = \left(273 K\right) \left(0.85 a t m\right) \left(0.35 L\right)$

$\left({T}_{2}\right) \left(0.92 L\right) = 81.22$

$\left({T}_{2}\right) = 88.3 K$