What is the the vertex of #x = (y +2)^2 - 5y-2 #?

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Answer 1 · 2018-06-14T14:04:45

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Answer 2 · 2018-06-14T14:10:02

#(7/4 , 1/2)#

#x = (y+2)^2-5y-2#

#x = (y^2 color(blue)(+4y) +4)color(blue)(-5y)-2#

#x = y^2 -y+2#

#x = (y- 1/2)^2 + 7/4#

#x- 7/4 = (y - 1/2)^2#

#"The vertex is at " (7/4,1/2)#